Answer:
Surface area of Tetrahedron is 62.4 square units.
Note:(This is for only one surface of Tetrahedron)
Step-by-step explanation:
Given :
The shape is Tetrahedron.
length of Base = 12 unit.
length of Height = 10.4 unit
To Find :
Surface area of Tetrahedron = ?
Solution:
Tetrahedron:
It is a polyhedron composed of
4 Triangular faces, ( four triangular surface)
6 Straight edges, and
4 Vertex corners.
Base Shape: Triangle
Side Shape: Triangle
We need to find surface area of Tetrahedron
[tex]\textrm{one surface area of a Tetrahedron} = \textrm{area of triangle}=\frac{1}{2}\times Base\times Height\\ =\frac{1}{2}\times 12\times 10.4\\=6\times 10.4\\=62.4\ unit^{2}[/tex]
Therefore, one side surface area of Tetrahedron is 62.4 square units.
If we required total surface area of the Tetrahedron then it will be multiplied by four, because it has 4 surface or 4 face.
Total surface area of Tetrahedron = 4 × 62.4
= 249.6 square units
