Answer:
The mathematical statement can be written as follows
[tex]\frac{2}{3}x-27\geq9[/tex]
which has solution as
⇒ [tex]x\geq54[/tex]
Step-by-step explanation:
Given:
Two thirds of a number decreased by 27 is at least 9.
This statement can be transformed into a mathematical statement.
Taking the unknown number as [tex]x[/tex] and putting the inequality [tex]\geq9[/tex] as the result is at least 9.
So, we have
[tex]\frac{2}{3}x-27\geq9[/tex]
Adding 27 both sides
[tex]\frac{2}{3}x-27+27\geq 9+27[/tex]
[tex]\frac{2}{3}x\geq 36[/tex]
Multiplying both sides by 3.
[tex]3\times\frac{2}{3}x\geq 36\times 3[/tex]
[tex]2x\geq108[/tex]
Dividing both sides by 2.
[tex]\frac{2x}{2}\geq\frac{108}{2}[/tex]
∴ [tex]x\geq54[/tex]
