Answer:
[tex]2x^2+12x+10=0[/tex]
Step-by-step explanation:
When you have the roots r1, r2 and the leading coefficient a of a quadratic equation, its factorization is
a(x - r1)(x - r2)
and the quadratic equation would be
a(x - r1)(x - r2) = 0
In this case r1 = -1, r2 = -5 and a = 2, so the quadratic equation is
[tex]\large 2(x-(-1))(x-(-5))=0\Rightarrow 2(x+1)(x+5)=0\Rightarrow\\\\\Rightarrow2(x^2+5x+x+5)=0\Rightarrow2(x^2+6x+5)=0\Rightarrow\\\\\boxed{2x^2+12x+10=0}[/tex]
