The velocity of the second ball is 1.2 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:
[tex]p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2[/tex]
where:
[tex]m_1 = 3.3 kg[/tex] is the mass of the first ball
[tex]u_1 = 1.3 m/s[/tex] is the initial velocity of the first ball
[tex]v_1 = 0[/tex] is the final velocity of the first ball
[tex]m_2 = 3.6 kg[/tex] is the mass of the second ball
[tex]u_2 = 0[/tex] is the initial velocity of the second ball
[tex]v_2[/tex] is the final velocity of the second ball
Re-arranging the equation and solving for v2, we find the velocity of the second ball after the collision:
[tex]v_2 = \frac{m_1 u_1}{m_2}=\frac{(3.3)(1.3)}{3.6}=1.2 m/s[/tex]
Learn more about momentum here:
brainly.com/question/7973509
brainly.com/question/6573742
brainly.com/question/2370982
brainly.com/question/9484203
#LearnwithBrainly
