Answer:
Magnitude of momentum of the sparrow [tex]=0.23\ kg\ ms^{-1}[/tex]
Explanation:
Given:
Mass of sparrow = 28 g = [tex]\frac{28}{1000}\ kg= 0.028\ kg[/tex]
Speed(velocity) of sparrow = [tex]8.1\ ms^{-1}[/tex]
Momentum of sparrow = [tex]mass\times velocity = 0.028 \times 8.1 = 0.2268\ kg\ ms^-1[/tex]
Momentum of sparrow in two significant figure can be given as [tex]=0.23\ kg\ ms^{-1}[/tex]
