Answer: 4 HCl (g) + O₂ (g) → 2 Cl₂ (g) + 2 H₂O (l)
Explanation:
4 moles of hydrogen chloride (note that it is in the gaseous phase, otherwise it would be hydrochloric acid) react with 1 mole of oxygen gas to form 2 moles of chlorine gas and 2 moles of liquid water.
To conform with the law of conservation of mass, the equation must be balanced, this means that there must be the same number of each type of atom on both sides of the arrow.
4HCl (aq) + O₂ (g) ⇒ 2Cl₂ (g) + 2H₂O (l)
Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:
For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:
Balancing C, H and the last O
Reaction :
HCl (aq) + O₂ (g) ⇒ Cl₂ (g) + H₂O (l)
Suppose we give a coefficient of 1 for HCl
HCl (aq) + aO₂ (g) ⇒ bCl₂ (g) + cH₂O (l)
number of Homs: left 1, right 2c -> 2c = 1-> c = 1/2
number of Cloms: left 1, right 2b ---> 2b = 1 ----> b = 1/2
number of O atoms: left 2a, right c ---> 2a = c ---> 2a = 1/2 ---> a = 1/4
the reaction coefficient becomes:
[tex]\rm HCl(aq)+\dfrac{1}{4}O_2(g)\Rightarrow \dfrac{1}{2}Cl_2(g)+\dfrac{1}{2}H_2O(l)\times 4\\\\4HCl(aq)+O_2(g)\Rightarrow 2Cl_2(g)+2H_2O(l)[/tex]
the combustion of octane in gasoline
brainly.com/question/8175791
brainly.com/question/897044
hydrogen and excess oxygen
brainly.com/question/1405182
