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Suppose your bicycle tire is fully inflated, with an absolute pressure of 7.00×105 Pa at a temperature of 21 °C. What is the pressure after its temperature has risen to 35.0ºC ? Assume that there are no appreciable leaks or changes in volume. Hint: At first, it may seem that not enough information is given, because the volume V and number of moles n are not specified. What we can do is use the equation twice: P0 V0 = nRT0 Pf Vf = nRTf . If we divide Pf Vf by P0 V0 we can come up with an equation that allows us to solve for Pf . Report the pressure in 105 Pa. For example, if the pressure is 7.36*105 Pa, just enter 7.36.

Respuesta :

Answer:

[tex]P_2 = 7.33 \times 10^5 Pa[/tex]

Explanation:

As we know that the tyre is fully inflated

So here we can say that the volume will remain constant

So we have

[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]

so here we have

[tex]P_1 = 7 \times 10^5 Pa[/tex]

[tex]T_1 = 273 + 21 = 294 k[/tex]

[tex]T_2 = (273 + 35) = 308 k[/tex]

now we have

[tex]\frac{7 \times 10^5}{294} = \frac{P_2}{308}[/tex]

[tex]P_2 = 7.33 \times 10^5 Pa[/tex]