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x=12 and y=18 satisfies both the equalities.

Step-by-step explanation:

Given equations are;

x/y = 2/3   Eqn 1

y/24 = 3/4   Eqn 2

Multplying by 24 on both sides of Eqn 2

[tex]24*\frac{y}{24}=\frac{3}{4}*24\\\frac{24y}{24}=\frac{72}{4}\\y=18[/tex]

Putting y=18 in Eqn 1;

[tex]\frac{x}{18}=\frac{2}{3}[/tex]

Multiplying both sides by 18

[tex]18*\frac{x}{18}=\frac{2}{3}*18\\\frac{18x}{18}=\frac{36}{3}\\x=12[/tex]

Putting both values in Eqn 1

[tex]\frac{12}{18}=\frac{2}{3}\\[/tex]

As 12 and 18 are multiples of 6;

[tex]\frac{2}{3}=\frac{2}{3}[/tex]

x=12 and y=18 satisfies both the equalities.

Keywords: fraction, division

Learn more about fractions at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

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Answer:

x = 6, y = 9

Step-by-step explanation:

You can solve y/12 = 3/4 because there is only one variable.

y = 3 · 12/4

Now we need to find x.

x = 9 · 2/3 = 18/3 = 6

The value of x can help us solve y.

6/y = 2/3

6 ÷ 2 = 3

3 · 3 = 9

y = 9

Finally, we know the values of both variables that can fit both equations.

x = 6

y = 9