Answer:
Step-by-step explanation:
Given that in a rural area, only about 30% of the wells that are drilled find adequate water at a depth of 100 feet or less.
The sample size n = 80
no of wells less than 100 feet deep=27
Sample proportion = [tex]\frac{27}{80} =0.3375[/tex]
a) Create hypotheses as
[tex]H_0: p = 0.30\\H_a: p >0.30\\[/tex]
(Right tailed test)
p difference [tex]= 0.3375-0.30 = 0.0375[/tex]
Std error of p = [tex]\sqrt{\frac{0.3(0.7)}{80} } =0.0512[/tex]
b) Assumptions: Each trial is independent and np and nq >5
c) Z test can be used.
Z= p diff/std error = [tex]\frac{0.0375}{0.0512} =0.73[/tex]
p value = 0.233
d) p value is the probability for which null hypothesis is false.
e) Conclusion: Since p >0.05 we accept null hypothesis
there is no statistical evidence which support the claim that more than 30% are drilled.