Answer:
E) 7.0 m/s
Explanation:
In situation A, by the mean of an energy balance:
[tex]1/2*m*V_a^2-1/2*K*\Delta X^2=0[/tex]
Solving for K:
K = 50000 N/m
For situation B:
[tex]1/2*m*V_b^2-1/2*K_t*\Delta X^2=0[/tex]
Where [tex]K_t=K+K=100000N/m[/tex]
Replacing this value and solving for Vb:
Vb = 7.07m/s
The answer is option E