Respuesta :

mkarikari1850

Answer:

3z^2 + 3z - 6 =0

3

3 (z^2 + z -2) = 0

3(z+2)(z - 1) = 0

z + 2-2 = 0 - 2

z = -2

z - 1 + 1 = 0 + 1

z = 1

Step-by-step explanation:

  1. factor out the GCF (3) and divide everything by it, and then set it equal to zero.
  2. since you have a degree of 2, factor it into two binomials that start with the square root of the first term and end with the square root of the second term.
  3. 3=0 is extraneous solution so we leave it, then we set each binomial equal to zero to solve for z.

note: your solutions is based on the degree or the exponent of the polynomial or the function.

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