Respuesta :
The school net ball team drew 2 matches. The team won [tex]\frac{5}{8}[/tex] of total matches played
Solution:
Given, A school netball team won ten matches, lost four and drew [tex]\frac{1}{8}[/tex] of the total played
Let the total number of matches played be "n"
Number of matches drawn = [tex]\frac{1}{8}[/tex] of n
Total matches played = number of won matches + number of lost matches + number of drawn matches
[tex]\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}[/tex]
Taking "n" as common from left hand side,
[tex]\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}[/tex]
So, they played 16 matches in total
Number of matches drawn = [tex]\frac{1}{8}[/tex] of n = [tex]\frac{1}{8} \times 16 = 2[/tex][tex]\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}[/tex]
[tex]\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }[/tex]
