Answer:
Answer is =0. 925 mol L−1
Explanation:
C₆H₁₂O₆ is formula of Glucose
For Molarity, we must know the following things
• the number of moles of solute present in solution
• the total volume of the solution
we know the mass of one mole of Glucose = 180.156 g/mol
Number of moles = Given Mass of substance / Mass of one mole
No of moles = 50g / 180.156 g/mol
= 0.277 moles
Now we know that molarity is expressed per liter of solution. Since you dissolve 0.277 moles of potassium chloride in 300. mL of solution, you can say that 1.0 L will contain
For 300 ml of solution, no of moles are = 0.277 moles
For 1 ml of solution, no of moles are = 0.277/300 moles
For 1(1000) ml of solution, no of moles are= 0. 277/300 x 1000
= 0.925 moles/ L
Answer is =0. 925 mol L−1
