contestada

The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:
3.01 x 103 J

3.99 x 102 J

-3.99 x 102 J

3.80 x 103 J

Respuesta :

Answer:[tex]3.01\times 10^{3}J[/tex]

Explanation:

Let [tex]T[/tex] be the temperature in kelvin.

Let [tex]KE[/tex] be the average kinetic energy.

Let [tex]n[/tex] be the number of moles.

Let [tex]R[/tex] be the universal gas constant.

As we know,

[tex]KE=\dfrac{3}{2}nRT[/tex]

Given,

[tex]n=1\\T=273-32=241K[/tex]

we know that [tex]R=8.314JK^{-1}mol^{-1}[/tex]

So,[tex]KE=\frac{3}{2} \times 1\times 8.314\times 241=3005.5J[/tex]=[tex]3.01\times 10^{3}J[/tex]