The equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0) is [tex]y=x^{2}-x-12[/tex]
We have to find the equation of a parabola that opens up and has the following x intercepts (-3, 0) and (4, 0)
x-intercepts of the parabola are (−3, 0) and (4, 0)
So, we can form an equation:
Also x = 4
x – 4 = 0
x – 4 = 0 is another factor of quadratic equation.
The quadratic function is:
[tex]\begin{array}{l}{y=(x+3)(x-4)} \\\\ {y=x^{2}-4 x+3 x-12} \\\\ {y=x^{2}-x-12}\end{array}[/tex]
Hence, the equation of the parabola is [tex]y=x^{2}-x-12[/tex]
