Answer:
Charlie used 4 20-cent stamps and 8 32-cent stamps.
Step-by-step explanation:
Let the number of 20 cents stamps be [tex]x[/tex]. Then, as per question, Chalie used twice as many 32-сent stamps as 20 cent stamps.
Therefore, number of 32-cent stamps is [tex]2x[/tex].
Now, total cost of the stamps is $ 3.36 = 336 cents
Cost of 1 20-cent stamp is 20 cents. So, cost of [tex]x[/tex] 20-cent stamps is [tex]20x[/tex]. Similarly, cost of [tex]2x[/tex] 32-cent stamps is [tex]32(2x)=64x[/tex]
Total cost = [tex]20x+64x=84x[/tex]
As per question,
[tex]84x=336\\x=\frac{336}{84}=4[/tex]
Number of 20-cent stamps = [tex]x = 4[/tex]
Number of 32-cent stamps = [tex]2x=2\times 4=8[/tex]
So, Charlie used 4 20-cent stamps and 8 32-cent stamps.
Answer:
No. of 32 cent stamps = 8
and that of 20 cent stamps = 4
Explanation:
Let no. of 32 cent stamps used be x and the number of 20 cent stamps used be y.
We are given that total postage on a package put by Charlie by using only 32 and 20 cent stamps is equal to $3.36.
So, since 100 cents make one dollar, $3.36 = 336 cents.
So,
32x + 20y = 336
Also we are given that Charlie used twice as many 32 cent stamps as 20 cent stamps which can be written as,
x = 2y
Substituting this equation in previous equation we get
32 [tex]\times[/tex]2y + 20y = 336
=> 64y + 20y = 336
=> 84y = 336
=>y = 4
Putting the value of y in x = 2y we get x = 2*4 = 8
So, no. of 32 cent stamps = 8 and that of 20 cent stamps = 4
