A car with an initial velocity of O m/s and a mass of 1500 kg reaches a velocity of 15 m/s in 5
seconds. What is the acceleration of the car? How much net force was required to reach
this acceleration?​

Respuesta :

Answer:the answer can be find out by the following steps;

Explanation:

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The acceleration of the car is [tex]3 m / s^{2}[/tex]. And the force required to reach the acceleration is 4500 N.

Explanation:

Equations of Motion describe different relations between motion parameters. One of them is,

                    [tex]v_{f}=v_{i}+a t[/tex]

And, [tex]F=m \times a[/tex] , from Newton’s laws

So, given,

Initial velocity of the car [tex]v_{i}[/tex] = 0  

Mass of the car, m = 1500 kg

Velocity acquired [tex]v_{f}[/tex] = 15 m/s

Time taken to acquire velocity t = 5 seconds.

Now, since  [tex]v_{f}=v_{i}+a t[/tex], To find the acceleration, rearrange the above equation, we get as follows,

               [tex]a=\frac{\left(v_{f}-v_{i}\right)}{t}[/tex]

Then, by applying the given data in above equation, we get

                [tex]a=\frac{(15-0)}{5}=\frac{15}{5}=3 m / s^{2}[/tex]

Now, find the force to reach [tex]3 m / s^{2}[/tex] acceleration as follows,

                [tex]F=m \times a=1500 \times 3=4500 N[/tex]