Answer:
Area of Larger square is [tex]20cm^2[/tex].
Step-by-step explanation:
Given:
Area of smaller Square = [tex]20cm^2[/tex].
Now to remove diagonal of smaller square we will use below formula.
Area of smaller circle = [tex]\frac{1}{2}\times diagnol^2[/tex]
[tex]\frac{1}{2}\times diagonal^2 =10\\ diagonal^2=10\times 2\\ diagonal^2=20\\diagonal=\sqrt{20} = \sqrt{4\times5}=\sqrt{2^2\times 5}=2\sqrt{5} \ cm[/tex]
Now diagonal of smaller square = diameter of circle= [tex]2\sqrt{5} \ cm[/tex]
Also diameter of circle = side of larger square = [tex]2\sqrt{5} \ cm[/tex]
hence area of larger square = [tex]side^2[/tex] = [tex](2\sqrt{5})^2=20 \ cm[/tex]
Area of Larger square is [tex]20cm^2[/tex].
