Answer:
Mass = 177.34 g
Explanation:
Given data:
Mass of Al₂O₃ = 67.7 g
Mass of HCl = 196.8 g
Mass of AlCl₃ = ?
Solution:
Chemical reaction:
Al₂O₃ +6 HCl → 2AlCl₃ + 3H₂O
Number of moles of Al₂O₃:
Number of moles = mass/ molar mass
Number of moles = 67.7 g / 101.96 g/mol
Number of moles = 0.664 mol
Number of moles of HCl:
Number of moles = mass/ molar mass
Number of moles = 196.8 g / 36.5 g/mol
Number of moles = 5.4 mol
Now we will compare the moles of AlCl₃ with HCl and Al₂O₃.
Al₂O₃ : AlCl₃
1 : 2
0.664 : 2×0.664 = 1.33 mol
HCl : AlCl₃
6 : 2
5.4 : 2/6×5.4 = 1.8 mol
The number of moles produced by Al₂O₃ are less so it will limiting reactant.
Mass of AlCl₃:
Mass = number of moles × molar mass
Mass = 1.33 mol × 133.34 g/mol
Mass = 177.34 g
