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Write the equation for the dissolution of Sr(N03)2 in water. How many moles of strontium ions and nitrate ions are produced by dissolving 0.5 mol of strontium nitrate?

Respuesta :

Answer:0.5 moles,1 mole

Explanation:

[tex]Sr(NO_{3})_{2}[/tex] is readily soluble in water.

[tex]Sr(NO_{3})_{2}[/tex] dissolves in water to give [tex]Sr^{2+}[/tex] ions and [tex]NO_{3}^{-}[/tex] ions.

The reaction is

[tex]Sr(NO_{3})_{2}[/tex]→[tex]Sr^{2+}[/tex][tex]+2NO_{3}^{-}[/tex]

So,[tex]1[/tex] mole of [tex]Sr(NO_{3})_{2}[/tex] gives [tex]1[/tex] mole of [tex]Sr^{2+}[/tex] and [tex]2[/tex] moles of [tex]NO_{3}^{-}[/tex].

So,[tex]0.5[/tex] moles of [tex]Sr(NO_{3})_{2}[/tex] gives [tex]0.5[/tex] moles of [tex]Sr^{2+}[/tex] and [tex]1[/tex] mole of [tex]NO_{3}^{-}[/tex].