Explanation:
[tex]Sr(NO_{3})_{2}[/tex] is readily soluble in water.
[tex]Sr(NO_{3})_{2}[/tex] dissolves in water to give [tex]Sr^{2+}[/tex] ions and [tex]NO_{3}^{-}[/tex] ions.
The reaction is
[tex]Sr(NO_{3})_{2}[/tex]→[tex]Sr^{2+}[/tex][tex]+2NO_{3}^{-}[/tex]
So,[tex]1[/tex] mole of [tex]Sr(NO_{3})_{2}[/tex] gives [tex]1[/tex] mole of [tex]Sr^{2+}[/tex] and [tex]2[/tex] moles of [tex]NO_{3}^{-}[/tex].
So,[tex]0.5[/tex] moles of [tex]Sr(NO_{3})_{2}[/tex] gives [tex]0.5[/tex] moles of [tex]Sr^{2+}[/tex] and [tex]1[/tex] mole of [tex]NO_{3}^{-}[/tex].