Sulfur trioxide can combine with water to form sulfuric acid. How many grams of sulfuric acid would be formed from 5.6368 mL of water?

Respuesta :

30.598 g of sulfuric acid

Explanation:

Sulfur trioxide (SO₃) will react with water (H₂O) to produce sulfuric acid (H₂SO₄):

SO₃ + H₂O → H₂SO₄

Now knowing the density of water is equal to 0.997 g/mL we calculate the mass of water:

density = mass / volume

mass = density × volume

mass of water = 0.997 × 5.6368 = 5.6199 g

number of moles = mass / molar weight

number of moles of water = 5.6199 / 18 = 0.31222 moles

From the chemical reaction we see that 1 mole of water produce 1 mole of sulfuric acid so 0.31222 moles of water will produce 0.31222 moles of sulfuric acid.

mass = number of moles × molar weight

mass of sulfuric acid = 0.31222 × 98 = 30.598 g

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