Answer:
(8, -3)
Step-by-step explanation:
The formula of a midpoint of AB
[tex]A(x_A,\ y_A),\ B(x_B,\ y_B)\\\\M_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)[/tex]
We have the points X(7, -5) and Y(9, -1).
Substitute:
[tex]M_{XY}\left(\dfrac{7+9}{2};\ \dfrac{-5+(-1)}{2}\right)\\\\M_{XY}\left(\dfrac{16}{2};\ \dfrac{-6}{2}\right)\\\\M_{XY}(8,\ -3)[/tex]
