Answer:
0.8 meters.
I just answered this ame question myself on a test I was taking.
Answer:
0.80m
Explanation:
The problem requires that we calculate the range covered by the diver, here the diver is assumed to be a particle undergoing projectile motion.
The range, R is given by equation (1);
[tex]R=\frac{u^2sin2\theta}{g}......................(1)[/tex]
where u is the initial velocity, [tex]\theta[/tex] is the angle of projection and g is acceleration due to gravity which is taken as [tex]9.8m/s^2[/tex].
Given;
u = 3.2m/s and [tex]\theta=25^o[/tex].
Substituting these into equation (1), we obtain the following;
[tex]R=\frac{3.2^2sin2(25)}{9.8}\\R=\frac{10.24*sin50}{9.8}\\R=\frac{10.24*0.7660}{9.8}\\R=0.80m[/tex]
