The puck takes 2.65 s to stop
Explanation:
The motion of the puck is a uniformly accelerated motion, so we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
In this problem, we have
u = 8.12 m/s
v = 0 (the puck comes to a stop)
[tex]a=-3.06 m/s^2[/tex] is the acceleration
So we can solve the equation to find t, the time the puck takes to come to a stop:
[tex]t=\frac{v-u}{a}=\frac{0-8.12}{-3.06}=2.65 s[/tex]
Learn more about accelerated motion:
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