What volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol)?

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25-11-2019
Chemistry

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What volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol)?

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okpalawalter8 okpalawalter8 · Answer 1 · 2021-10-22T14:36:02+02:00

We have that for the Question "What volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol)?" it can be said that The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is

V=0.862L

From the question we are told

What volume of 0.20MNaCl (aq) contains 10.0g of NaCl (molar mass 58g/mol)?

Generally the equation for the morality is mathematically given as

[tex]M=\frac{moles of NaCl}{Volume of sol}\\\\0.20=\frac{10/58}{V}\\\\[/tex]

V=0.862L

Therefore

The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is

V=0.862L

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tutorareej tutorareej · Answer 2 · 2021-10-26T11:33:27+02:00

The volume of 0.20M NaCl solution containing 10g of NaCl will be 34.48 ml.

Molarity can be defined as the moles of solute in a liter of solution.

The 10 g of NaCl will be:

[tex]\rm moles\;=\;\dfrac{weight}{molecular\;weight}[/tex]

moles of NaCl = [tex]\rm \dfrac{10\;g}{58\;g/mol}[/tex]

Moles of NaCl = 0.172 moles

[tex]\rm Molarity\;=\;\dfrac{moles}{Volume\;(liters)}[/tex]

[tex]\rm Volume\;(liters)\;=\;moles\;\times\;molarity[/tex]

Volume of NaCl solution = 0.172 [tex]\times[/tex] 0.20

Volume of NaCl solution = 0.0344 liters

1 liter = 1000 ml

0.0344 liters = 0.0344 [tex]\times[/tex] 1000 ml

Volume of 0.20M NaCl solution containing 10g of NaCl will be 34.48 ml.

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