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3. If the line tangent to the graph of the function f at the point (1,7) also passes through the point
(-2,-2), then what is the value of f'(1)?

Respuesta :

SvetkaChem

Answer:

f'(-1)= 3

Step-by-step explanation:

slope = (y2 - y1)/(x2 - x1)= (7-(-2))/(1-(-2))=9/3=3

Slope of the tangent line in the given point equals f' at this point.

So,

f'(-1)= 3

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