Two parallel lines are crossed by a transversal.

Horizontal and parallel lines s and r are cut by transversal t. At the intersection of lines s and t, the uppercase left angle is 115 degrees. At the intersection of lines r and t, the uppercase left angle is x degrees.
What is the value of x?

x = 45
x = 65
x = 95
x = 115

Question

contestada

Respuesta :

lublana lublana · Answer 1 · 2019-12-24T06:50:32+01:00

Answer:

x=[tex]115^{\circ}[/tex]

Step-by-step explanation:

We are given that

Parallel lines s and r are cut by transversal line t.

At the intersection of line s and t

The uppercase left angle=[tex]115^{\circ}[/tex]

At the intersection of r and t

The uppercase left angle =x

We have to find the value of x

We know that when two lines are parallel and cut by transversal line then, corresponding angles are equal.

[tex]\angle x=115^{\circ}[/tex]

Reason: corresponding angles are equal

Hence, the value of x=[tex]115^{\circ}[/tex]

akposevictor akposevictor · Answer 2 · 2021-10-01T17:27:17+02:00

The value of x is: D. 115 degrees

The figure showing parallel lines s and r that are intersected by transversal t, is shown in the attachment below.

The angle measuring 115 degrees is an exterior angle on the same side along transversal t where angle x also lies.

Corresponding angles are congruent, therefore,

x = 115 degrees.

We can conclude therefore, that:

the value of x = 115 degrees.

Learn more here:

https://brainly.com/question/9622564