The work done is 6958 J
Explanation:
The work done by the man to raise the weight is the equal to the increase in gravitational potential energy of the weight, so we can write:
[tex]W=mg \Delta h[/tex]
where
(mg) is the weight, with m being the mass and g the acceleration of gravity
[tex]\Delta h[/tex] is the change in height of the weight
In this problem, we have
mg = 710 N (weight)
[tex]\Delta h = 0.65 m[/tex]
Therefore, the work done is
[tex]W=(710)(9.8)=6,958 J[/tex]
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The work done is 461.5 J.
Explanation:
According to Kinetics, the work done is calculated as the product of force which has done work, and the displacement it has imposed. Hence,
[tex]\text {Work done}=F \times s[/tex]
In the problem, the given data, F = 710 N and s = 0.65 m
By applying the given values to the work done equation, we get as follows,
[tex]\text { Work done } = 710 \times 0.65 = 461.5 \mathrm{J}[/tex]
The unit is same as the energy, work done defines when 1 N force acts in a 1 m distance along the force’s direction.
