Answer:
[tex]T_n= 9+(n-1)[/tex]
Step-by-step explanation:
The Given sequence is 9, 10, 11, 12
We need to find the expression to describe the sequence.
Let [tex]T_n[/tex] be the [tex]n^{th}[/tex] term of the sequence.
Let n represent the position of the term.
Let a be the first term in the sequence.
and d be the common difference between the sequence
Hence the expression to find the above sequence is given below;
[tex]T_n= a+(n-1)d[/tex]
when n=1 d= 1 a = 9
[tex]T_1 = 9+(1-1)1 = 9 + 0 = 9[/tex]
when n=2 d= 1 a = 9
[tex]T_2 = 9+(2-1)1 = 9 + 1 = 10[/tex]
when n=3 d= 1 a = 9
[tex]T_3 = 9+(3-1)1 = 9 + 2 = 11[/tex]
when n=3 d= 1 a = 9
[tex]T_4 = 9+(4-1)1 = 9 + 3 = 12[/tex]
Hence the expression is [tex]T_n= 9+(n-1)[/tex]
