Answer: The volume of the gas when the pressure and temperature has changed is [tex]629.2cm^3[/tex]
Explanation:
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1,V_1\text{ and }T_1[/tex] are the initial pressure, volume and temperature of the gas
[tex]P_2,V_2\text{ and }T_2[/tex] are the final pressure, volume and temperature of the gas
We are given:
[tex]P_1=1.7atm\\V_1=377cm^3\\T_1=41.7^oC=[41.7+273]K=314.7K\\P_2=0.958atm\\V_2=?cm^3\\T_2=23^oC=[23+273]K=296K[/tex]
Putting values in above equation, we get:
[tex]\frac{1.7atm\times 377cm^3}{314.7K}=\frac{0.958atm\times V_2}{296K}\\\\V_2=\frac{1.7\times 377\times 296}{314.7\times 0.958}=629.2cm^3[/tex]
Hence, the volume of the gas when the pressure and temperature has changed is [tex]629.2cm^3[/tex]