Answer:
Moles of gas collected = 0.952 mole
Explanation:
To calculate the number of moles of the gas collected, we use the equation given by ideal gas which follows:
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 702 mmHg
V = Volume of the gas = 25.0 L
T = Temperature of the gas = [tex]22.5^oC=[22.5+273.15]K=295.65\ K[/tex]
R = Gas constant = [tex]62.3637\text{ L.mmHg }mol^{-1}K^{-1}[/tex]
n = number of moles of gas = ?
Putting values in above equation, we get:
[tex]702\ mmHg\times 25.0\ L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 295.65\ K\\\\n=\frac{702\times 25}{62.3637\times 295.65}\ mol=0.952mol[/tex]
Moles of gas collected = 0.952 mole
