Answer:
The standard potential for this galvanic cell is 1.25 V
Explanation:
Step 1
Oxidation: Fe(s) → Fe^2+ (aq) + 2e- E° = 0.447 V
Reduction: Ag+(aq) + e- → Ag(s) E° = 0.7996 V
The electron number for the oxidation is 2; the electron number for the reduction is 1.
By multiplying the reduction reaction by 2, we make the electron number the same between the two half-equations
2 Ag+(aq) + 2e- → 2Ag(s) E° = 0.7996 V
Step 2: The overall balanced equation
Fe(s) + 2Ag+(aq) → Fe^2+(aq) + 2ag(s) E° = 0.447 V + 0.7996 V = 1.25V
The standard potential for this galvanic cell is 1.25 V
