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The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 10.4degrees. If skyscraper B is 1472 feet​ tall, how far apart are the two​ skyscrapers? Assume the bases of the two buildings are at the same elevation.

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sqdancefan

Answer:

  8020 feet

Step-by-step explanation:

The tangent relation can be used to answer this question, since it relates the sides of a right triangle to the acute angle.

 tan(elevation angle) = (1472 ft)/(distance between)

Then ...

  distance between = (1472 ft)/tan(10.4°) ≈ 8020 ft

The skyscrapers are 8020 feet apart.

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