Answer:
53
Step-by-step explanation:
Given: The sum of two digit number is 8
Reversing the digit will get us number 18 less than the original.
Lets take x as tenth digit of our number and y as unit digit of our number.
As given sum of digit is 8
∴ [tex]x+y= 8[/tex]
∴ [tex]y= 8-x[/tex] - equation 1
We also know that reversing the digit will get us number 18 less than the original.
∴ [tex]10y+x = 10x +y-18[/tex]
Now, lets put the value of y from equation 1
⇒ [tex]10(8-x) + x = 10x+ (8-x)- 18[/tex]
⇒ [tex]80-9x= 9x-10[/tex]
⇒ [tex]90= 18x[/tex]
∴ [tex]x= 5[/tex]
Next, substituting the value of x in equation 1
[tex]y= 8-x[/tex]
⇒ [tex]y= 8-5 = 3[/tex]
∴ [tex]y= 3[/tex]
∴ The original number is 53, sum of the digit is 8 and if we reverse the digit of the number, we get 35, which is 18 less than the original number.
