Integrals with variables.

Answer:
a = 5, b = 14
Step-by-step explanation:
∫₁¹⁴ f(x) dx is the area under f(x) between x = 1 and x = 14.
∫₁⁵ f(x) dx is the area under f(x) between x = 1 and x = 5.
Therefore, the difference is the area under f(x) between x = 5 and x = 14.
∫₁¹⁴ f(x) dx − ∫₁⁵ f(x) dx = ∫₅¹⁴ f(x) dx