Answer:
C) the magnitude of the acceleration is a minimum.
Explanation:
As we know that ,the general equation of the simple harmonic motion given as
The displacement x given as
x=X sinω t
Then the velocity v will become
v= X ω cosωt
The acceleration a
a= - X ω² sinω t
The speed of the particle will be maximum when cosωt will become 1 unit.
It means that sinωt will become zero.So acceleration and displacement will be minimum.
Therefore when speed is maximum then acceleration will be minimum.
At the mean position the speed of the particle is maximum that is why kinetic energy also will be maximum and the potential energy will be minimum.
Therefore option C is correct.
