Respuesta :

nkirotedoreen46

Answer:

The pressure increases by 10% of the original pressure

Thus the new pressure is 1.1 times the original pressure.

Explanation:

We are given;

  • Initial temperature as 30°C, but K = °C + 273.15
  • Thus, Initial temperature, T1 =303.15 K
  • Final temperature, T2 is 333.15 K

We are required to state what happens to the pressure;

  • We are going to base our arguments to Pressure law;
  • According to pressure law, the pressure of a gas and its temperature are directly proportional at a constant volume
  • That is; P α T
  • Therefore, at varying pressure and temperature

[tex]\frac{P1}{T1}=\frac{P2}{T2}[/tex]

Assuming the initial pressure, P1 is P

Rearranging the formula;

[tex]P2=\frac{P1T2}{T1}[/tex]

[tex]P2=\frac{(P)(333.15K)}{303.15K}[/tex]

     [tex]P2 = 1.099P[/tex]

                 = 1.10 P

The new pressure becomes 1.10P

This means the pressure has increased by 10%

We can conclude that, the new pressure will be 1.1 times the original pressure.

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