The velocity after 3 s is 12 m/s rightward
Explanation:
The motion of the rocket is a motion at constant acceleration, therefore we can apply suvat equations:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time interval
For the rocket in this problem:
u = 0 (the rocket starts from rest)
t = 3 s
[tex]a=4 m/s^2[/tex] rightward is the acceleration
Solving for v, we find the final velocity:
[tex]v=0+(4)(3)=12 m/s[/tex] (rightward)
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