Answer:
Force, |F| = 1360.24 N
Explanation:
It is given that,
Water from a fire hose is directed horizontally against a wall at a rate of 69.4 kg/s, [tex]\dfrac{m}{t}=69.4\ kg/s[/tex]
Initial speed of the water, u = 19.6 m/s
Finally water comes to stop, v = 0
To find,
The magnitude of the force exerted on the wall.
Solution,
Let F is the force exerted on the wall. The product of mass and acceleration is called the force exerted. Using second law of motion to find it as :
[tex]F=m\dfrac{v-u}{t}[/tex]
[tex]F=\dfrac{-mu}{t}[/tex]
[tex]F=-69.4\ kg/s\times 19.6\ m/s[/tex]
|F| = 1360.24 N
So, the magnitude of the force exerted on the wall is 1360.24 N.
