20 points , will mark brainiest :)

A ) 5 × 10³ + 4 × 10² + 1 × [tex]10^{1}[/tex] + 7 × [tex]10^{0}[/tex] + 4 × [tex]\frac{1} {10^{1}}[/tex] + 1 × [tex]\frac{1}{10^{2}}[/tex] + 2 × [tex]\frac{1}{10^{3}}[/tex]

Or , 5000 + 400 + 10 + 7 × 1 + 0.4 + 0.01 + 0.002

or, ( 5400 + 10 + 7 ) + ( 0.4 + 0.01 + 0.002 )

Or, 5417 + 0.412

Or, 5417.412

Hence The sum of given digits is 5417.412

B ) 4 × 10² + 1 × ( 1 [tex]\frac{1} {10^{1}}[/tex] ) + 3 × [tex]\frac{1}{10^{3}}[/tex]

Or, 400 + 1 × ([tex]\frac{10+1}{10}[/tex] ) + 0.003

Or, 400 + [tex]\frac{11}{10}[/tex] + 0.003

Or, 400 + 1.1 + 0.003

Or, 401.103

Hence The sum of given digits is 401.103

Answer

KerryEye KerryEye · Answer 2 · 2019-12-01T12:59:21+01:00

Answer:

1) 5417.412

2) 401.13

Step-by-step explanation:

1) [tex]$ 5 \times 10^3 + 4 \times 10^2 + 1 \times 10^1 + 7 \times 10^0 + 4 \times \frac{1}{10^1} + 1 \times \frac{1}{10^2} + 2 \times \frac{1}{10^3} $[/tex]

[tex]$ 5 \times 10^3 = 5000 $\\ $ 4 \times 10^2 = 400 $ \\ $ 1 \times 10^1 = 10 $\\$ 7 \times 10^0 = 7 \times 1 = 7 $\\$ 4 \times \frac{1}{10^1} = 0.4 $\\$ 1 \times \frac{1}{10^2} = 0.01 $\\ $ 2 \times \frac{1}{10^3} = 0.02 $ \\[/tex]

Combining we have: [tex]$ 5000 + 400 + 10 + 7 + 0.4 + 0.01 + 0.002 = $[/tex] 5417.412.

2) [tex]$ 4 \times 10^2 + 1 \times 1\frac{1}{10^1} + 3 \times \frac{1}{10^2} $[/tex]

[tex]$ 4 \times 10^2 = 400 $\\$ 1 \times 1\frac{1}{10^1} = 1 \times \frac{11}{10} = 1 \times 1.1 = 1.1 $\\$ 3 \times \frac{1}{10^2} = 0.03 $[/tex]

Combining we have: 400 + 1.1 + 0.03 = 401.13.

Hence, we have the answers.