Answer
given,
radius of tire = 25 cm = 0.25 m
initial velocity = 0 m/s
final velocity = 30 m/s
time = 10 s
a) acceleration with respect to center
v = u + a t
30 = 0 + 10 a
a = 3 m/s²
radial acceleration
[tex]a_r = \dfrac{v^2}{r}[/tex]
[tex]a_r = \dfrac{2^2}{0.25}[/tex]
[tex]a_r =16\ m/s^2[/tex]
[tex]a=\sqrt{a_r^2 + a_t^2}[/tex]
[tex]a=\sqrt{16^2 + 3^2}[/tex]
[tex]a=16.28\ m/s[/tex]
acceleration w.r.t center of tire = [tex]a=16.28\ m/s[/tex]
b) acceleration with respect to road will be equal to 3 m/s²
