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A chemist carefully measures the amount of heat needed to raise the temperature of a 894.0 g sample of a pure substance from -5.8C to 17.5C. The experiment shows that 4.90kJs of heat are needed. What can the chemist report for the specific heat capacity of the substance? (Round your answer to 3 significant digits.)

Respuesta :

Answer : The specific heat of substance is [tex]0.235J/g^oC[/tex]

Explanation :

Formula used :

[tex]Q=m\times c\times \Delta T[/tex]

or,

[tex]Q=m\times c\times (T_2-T_1)[/tex]

where,

Q = heat needed = 4.90 kJ  = 4900 J

m = mass of sample = 894.0 g

c = specific heat of substance = ?

[tex]T_1[/tex] = initial temperature  = [tex]-5.8^oC[/tex]

[tex]T_2[/tex] = final temperature  = [tex]17.5^oC[/tex]

Now put all the given value in the above formula, we get:

[tex]4900J=894.0g\times c\times [17.5-(-5.8)]^oC[/tex]

[tex]c=0.235J/g^oC[/tex]

Therefore, the specific heat of substance is [tex]0.235J/g^oC[/tex]

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