Answer:
0.174 M
Explanation:
The same can be solve by using Nernst's equation
The Nernst's equation is:
[tex]Ecell=E^{0}_{cell}-\frac{0.0592}{n}log\frac{[anodic]}{[cathodic]}[/tex]
For silver cell
n= 1
As both the compartments have silver nitrate solution,t the standard emf of cell will be zero.
Given
Ecell = 0.045
[Anodic compartment]= 1 M
Putting values
[tex]0.045 = 0 -\frac{0.0592}{1}log(\frac{1}{x} )[/tex]
[tex]0.760=log(\frac{1}{x})[/tex]
Taking antilog and solving
[AgNO3]=0.174 M