Solve the given triangle. Round the measures of sides to the nearest tenth and measures of angles to the nearest degree. c = 8, B = 50°, C = 55°
Question 15 options:


A. A = 75°, a = 63.6, b = 7.5

B. A = 75°, a = 7.5, b = 9.4

C. A = 75°, a = 9.4, b = 7.5

D. A = 75°, a = 8, b = 7.5

Respuesta :

Answer:

A = [tex]75^o[/tex], a = 9.4 , and b = 7.5 (which coincides with option C among the listed possible answers)

Step-by-step explanation:

First, we can find the length of side b through the law if sines:

[tex]\frac{b}{sin(B)} = \frac{c}{sin(C)}\\b=\frac{c\,*\,sin(B)}{sin(C)}\\ b=\frac{8\,*\,sin(50^o)}{sin(55^o)}\\b=7.481[/tex]

That we can round to 7.5

Now we can find angle A using the property that the addition of all angles in a triangle must equal [tex]180^o[/tex]:

[tex]A+B+C=180^o\\A+50^o+55^o=180^o\\A=180^o-50^o-55^o\\A=75^o[/tex]

And finally, we can find side "a" by using again the law of sines:

[tex]\frac{a}{sin(A)} = \frac{c}{sin(C)}\\a=\frac{c\,*\,sin(A)}{sin(C)}\\ a=\frac{8\,*\,sin(75^o)}{sin(55^o)}\\a=9.4334[/tex]

which can be rounded to a = 9.4

Answer:

C. A = 75°, a = 9.4, b = 7.5 is correct.

Step-by-step explanation: