Respuesta :
Answer:
a) [tex]\frac{1}{3}[/tex]
b) [tex]\frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...[/tex]
Step-by-step explanation:
Number of balls in the urn = 12
Number of white balls in the urn = 4
So, number of balls which are not white = 12 - 4 = 8
We know that probability = No. of outcomes/Total number of outcomes
Let [tex]A_i\,,\,B_i\,,\,C_i[/tex] denotes the event of getting white ball by A, B and C
a) each ball is replaced after being drawn.
Probability = Number of white balls/Total number of balls
Solution: [tex]P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}[/tex]
b)the balls that are withdrawn are not replaced.
Solution:
If A wins: [tex]P(A_1)=\frac{4}{12}=\frac{1}{3}[/tex]
If A lost and B wins: [tex]P\left ( B_1|A_1^{c} \right )=\frac{4}{11}[/tex]
If A and B lost and C wins: [tex]P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}[/tex]
and so on....
