Answer:
There is no enough evidence that the viscosity is not 3000. The viscosity is not significantly different from 3000.
Step-by-step explanation:
We have to perform an hypothesis test on the mean.
The null and alternative hypothesis are:
[tex]H_0: \mu=3000\\\\H_1:\mu\neq3000[/tex]
The significance level is 0.05.
The mean of the sample is:
[tex]M=(1/5)*(2781+2900+3013+2856+2888)=2887.6[/tex]
The standard deviation of the sample is:
[tex]s=\sqrt{\frac{1}{5-1}*[(2781-2887.6)^2 +(2900-2887.6)^2 +...]}=84.0[/tex]
The statistic t can be calculated as:
[tex]t=\frac{M-\mu}{s} =\frac{2887.6-3000}{84} =-1.338[/tex]
The degrees of freedom are [tex]df=N-1=5-1=4[/tex]
The P-value for t=-1.338 and df=4 is P=0.2519. The P-value is greater than the significance level, so it failed to reject the null hypothesis.
There is no enough evidence that the viscosity is not 3000.
