Answer:
102.6 g
Explanation:
Firstly, let's understand the terms used in the question. Semi-molar solution is a solution which has a molarity of:
[tex]c=\frac{1}{2} M=0.5 M[/tex]
We're given the molar mass of:
[tex]M=342 \frac{g}{mol}[/tex]
Let's use the definition of molarity: molarity is the ratio between the moles of solute and the volume of solution:
[tex]c=\frac{n}{V}[/tex]
From here, we wish to express moles, n, as the ratio of mass of sucrose to its molar mass:
[tex]n=\frac{m}{M}[/tex]
Substitute it back into the equation of molarity:
[tex]c=\frac{n}{V}=\frac{\frac{m}{M} }{V}=\frac{m}{MV}[/tex]
Since we wish to find mass, let's multiply both sides of the equation by MV to obtain mass equation:
[tex]m=cMV[/tex]
Now, convert volume into liters knowing that 1 mL = 1 cm³ and 1000 mL = 1 L:
[tex]600 cm^3 \cdot\frac{1 mL}{1 cm^3} \cdot \frac{1 L}{1000 mL} =0.600 L[/tex]
Substitute all three variables into the equation:
[tex]m=0.5 M\cdot342 \frac{g}{mol}\cdot0.600 L=102.6 g[/tex]
