contestada

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 54 -3. What is the point slope
form of the equation for this line?
y-13 = 564 - 2)
y- 13 = 5(x + 2)
y-2 = 5(4, - 13)
y+ 2 = 544 - 13)

Respuesta :

Answer:

[tex]y+13=5(x+2)[/tex]

Step-by-step explanation:

The correct question is

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3. What is the point slope  form of the equation for this line?

we have

[tex]y=5x-3[/tex]

This is the equation of the line in slope intercept form

where

the slope is [tex]m=5[/tex]

the y-intercept is [tex]b=-3[/tex]

Remember that

The equation of the line in point-slope form is equal to

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]m=5[/tex]

[tex]point\ (-2,-13)[/tex]

substitute

[tex]y-(-13)=5(x-(-2))[/tex]

[tex]y+13=5(x+2)[/tex]