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Jane, Fay, and Henry had a total of $90. After Jane gave $12 to Henry and Fay gave $2 to Jane, all three of them had the same amount of money. How much money did each of them have in the beginning?

Respuesta :

sam4040

Answer:

[tex]Jane= 40\$\\ Fay=32\$\\Henry=18\$[/tex]

Step-by-step explanation:

Let jane had money [tex]=x\$[/tex]

Fay had money [tex]=y\$[/tex]

Henry had money [tex]=z\$[/tex]

Total money [tex]=90\$[/tex]

[tex]x+y+z=90[/tex]

Jane gave [tex]12\$[/tex] to Henry

Henry[tex]=z+12\$[/tex]

Jane[tex]=x-12\$[/tex]

Fay gave [tex]2\$[/tex] to Jane

[tex] Jane=x-12+2=x-10\\Fay=y-2\\\\ x-10=y-2=z+12\\x-10=y-2\\y=x-8\\\\x-10=z+12\\z=x-22\\\\x+y+z=90\\x+x-8+x-22=90\\3x-30=90\\3x=120\\x=40\\\\y=40-8\\y=32\\\\z=x-22\\=40-22\\=18[/tex]

201600823

Answer:

Jane has $40

Fay has $32

Henry has $18

Notes:

I worked hard to figure this out--could I (maybe) get Brainliest?

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