andreedwards5451 andreedwards5451

22-12-2019
Mathematics

contestada

Two buses leave towns 1015 miles apart at the same time and travel toward each other. One bus travels 11 miles/hr slower than the other. If they meet in 7 hours, what is the rate of each bus?

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jcherry99 jcherry99

22-12-2019

Answer:

Step-by-step explanation:

Bus One

speed = x

t = 7 hours

d = ?

Bus two

speed = x + 11

time = 7 hours

d1 = 1015 miles - d

Equations

d = s * t

Bus 1 + bus 2 = 1015

Solution

x * 7 + (x + 11)*7 = 1015

7x + 7x + 11*7 = 1015

14x + 77 =1015

14x + 77 - 77 = 1015 - 77

14x = 938

14x/14 = 938/14

x = 67 miles / hour

x + 11 = 78 miles / hour

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